Set reflective boundary condition for pin by pin hexagonal problem

User Support
1

Hi everyone,

I have a pin by pin (ONLY have 7 pins in total) hexagonal benchmark problem, the outer boundary conditon is reflective. My question is how to set boundary condition for this problem?

Thanks a lot. Sorry to post this question again.

Li

plot_xy
plot_xy1100×1100 4.64 KB

2

@jerrylizy You would need to set the boundary condition for each of the planar surfaces that compose the outer boundary to be reflective.

3

Dear @paulromano,

I got the same problem and I’ve tried to apply your suggestion. However, some of the surfaces defining the outer boundary “cuts” the domain, resulting in unwanted reflection inside the domain.

For example, given @pitch as the pitch of a single hexagon, supposing we’re looking at a figure in the xy plane, I can easily define a YPlane at 1.5@pitch in order to bound the top part of the domain. On the other hand, if I want to bound the top of the 2 green haxagons, I would need to define a YPlane at @pitch, but this plane would cut the top indingo hexagon, causing unwanted reflection in this region.

How can I solve this type of problem?

Thank you in advance for your support